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2\(x\) – 3 + 3 = 2\(x\) and −7 + 3 = −4 ... 8 – 𝒙 + 𝒙 = 8 and 5 + 𝒙 = 5 + 𝒙 Image caption, The equation 8 = 5 + 𝒙 can be solved by subtracting 5 from both sides of the ...

Rewrite \(y = {x^2} - 6x + 11\) in the form \(y = {(x - b)^2} + c\). To get \(b\) (the number inside the bracket), halve the coefficient (number in front) of the second term in the original equation.